Question:

0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10 m³ at 1000 K. Given R is the gas constant in JK⁻¹mol⁻¹, x is:

2R4+12

4+R2R

4−R2R

2R4−2

Given that nT=(0.5+x); T=1000K; V=10m³; P=200Pa
Now, PV=n×R×T
200×10=(0.5+x)×R×1000
2=(0.5+x)R
2R=0.5+x
2R=1/2+x
4R=1+2x
4R-1=2x
2R-1/2=x