t₁₂ = 8 days = 8 × 24 hr
R₀ = 2.4 × 10⁵ Bq
Using 0.693/t₁₂ × t = ln(R₀/R)
0.693/(8 × 24) × 11.5 = ln(2.4 × 10⁵/R)
2.4 × 10⁵/R = e⁰·⁰⁴¹ = 1 + 0.041
R = 2.4 × 10⁵/1.041 = 2.3 × 10⁵
115 Bq is in volume = 2.5 ml
2.3 × 10⁵ Bq is in volume = 2.5 × (2.3 × 10⁵)/115 = 0.05 × 10⁵ = 5 × 10³ ml = 5 liters