18 g of glucose, C6H12O6 (Molar Mass = 180 g/mol) is dissolved in 1 kg of water in a saucepan. At what temperature will this solution boil?

We calculate the change of the boiling point if we will use the equation:
ΔT = Kb × molality

molality = moles of solute / Weight of solvent (in kg) = 18/180

Substituting the value we get,
ΔTb = 0.05

So, the temperature at which the solution will boil
Tb = 373.15 + 0.05 = 373.2 K