96500 g of Ag
10.8 g of Ag
half of electrochemical equivalent of Ag
electrochemical equivalent of Ag
The correct option is B electrochemical equivalent of Ag
From Faraday's first law,
w=Z×Q
When Q=1 C
Z=108/1=108
w=Z
Where Z=electrochemical equivalent of Ag.
Hence, option B is correct.