200 g of water is heated from 40°C to 60°C. Ignoring the slight expansion of water, the change in its internal energy is close to: (Given specific heat of water = 4184 J/kg/K)
8.4 kJ
167.4 kJ
4.2 kJ
16.7 kJ
Solution:
The correct option is B (16.7 kJ)
Since expansion is ignored, work done is zero and hence by the first law of thermodynamics, internal energy change equals heat supplied. ΔU = Q = 0.2(4184)(20) J = 16.7 kJ