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Question:

3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the products: Four Six Zero Two

Four

Six

Two

Zero

Solution:

The correct option is C
Four
3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. A molecule of HBr is added to C=C double bond. The addition follows anti-Markowikoff's rule. Br is added to less substituted C atom. The number of possible stereoisomers for the products is four. The product has 2 chiral C atoms and is unsymmetrical. Hence, 4 stereoisomers are possible.