5.2 moles of aqueous solution of 1 L of methyl alcohol (CH3OH) is supplied. What is the mole fraction of methyl alcohol in the solution?

The solution contains 5.2 moles of CH3OH. Assuming the density of water is approximately 1 g/mL, 1 L of water weighs 1000 g, which is equal to 1000 g / 18.015 g/mol = 55.51 moles of water.

The total number of moles in the solution is 5.2 moles (CH3OH) + 55.51 moles (H2O) = 60.71 moles.

The mole fraction of methyl alcohol (CH3OH) is calculated as:

Mole fraction of CH3OH = (moles of CH3OH) / (total moles)

Mole fraction of CH3OH = 5.2 moles / 60.71 moles ≈ 0.086

Therefore, the mole fraction of methyl alcohol in the solution is approximately 0.086.