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Question:

A 0.2 kg object at rest is subjected to a force (0.3î - 0.4ĵ) N. What is the velocity after 6s?

(8î - 16ĵ)

(12î - 9ĵ)

(9î - 12ĵ)

(16î - 8ĵ)

Solution:

Force acting on an object = →F = d→p/dt ⇒ Δ→p = ∫₀ᵗ →F dt ⇒ →pf - 0 = (0.3î - 0.4ĵ) × 6 kg m/s ⇒ →vf = (9î - 12ĵ) N