A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38Ω as shown in the figure. Find the value of the current in the circuit.
Solution:
The net potential difference applied across the resistor = 200V - 10V = 190V The resistance of the resistor = 38Ω Hence current through the resistor = 190V / 38Ω = 5A