Question:

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time (i) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of a pole which casts a shadow 5 m long.

(i) x₁/y₁ = x₂/y₂ ⇒ 5.6/3.2 = 10.5/y₂ ⇒ y₂ = 6 cm
(ii) x₁/y₁ = x₃/y₃ ⇒ 5.6/3.2 = x₃/5 ⇒ x₃ = 8.75 m