2V
0.2V
2 × 10⁻³V
0.02V
Correct option is D. 0.02V
Magnetic field B = 5 × 10⁻⁵ T
Number of turns in coil N = 800
Area of coil A = 0.05 m²
Time taken to rotate Δt = 0.1 s
Initial angle θ₁ = 0°
Final angle θ₂ = 90°
change in magnetic flux ΔΦ = NBAcos90° − BAcos0° = −NBA = −800 × 5 × 10⁻⁵ × 0.05 = −2 × 10⁻³ weber
e = −ΔΦ/Δt = −(−2 × 10⁻³ Wb) / 0.1 s = 0.02V