A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball, find the number of blue balls in the bag.
Solution:
Let there be x blue balls. So, the total number of balls = x + 5 P(Blue ball) = x/(x+5) P(Red ball) = 5/(x+5) Given, P(Blue) = 2 × P(Red) x/(x+5) = 2 × 5/(x+5) Solving, we get x as 10. So, the number of blue balls = 10.