A block is moving on an inclined plane making an angle of 45° with the horizontal and the coefficient of friction is μ. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define N = 10μ, then N is?<p></p>

From figure:
F1 = mg(sinθ - μcosθ)
F2 = mg(sinθ + μcosθ)

Given that F2 = 3F1, we have:

mg(sinθ + μcosθ) = 3mg(sinθ - μcosθ)

sinθ + μcosθ = 3sinθ - 3μcosθ

4μcosθ = 2sinθ

2μcosθ = sinθ

Since θ = 45°, sinθ = cosθ = 1/√2

2μ(1/√2) = 1/√2

2μ = 1

μ = 1/2

Given N = 10μ, we have:

N = 10 * (1/2) = 5

Question: