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Question:

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P, such that the block does not move downward?

25N

18N

32N

44N

Solution:

The correct option is A
32N
mgsin45° = 10 × 9.8 × 1/√2 = 50√2
μmgcosθ = 0.6 × mg × 1/√2 = 0.6 × 50√2
P = 3 + 0.6 × 50√2 = 3 + 42.43 = 45.43 ≈ 44N