The instantaneous speed at x0 of the combined masses decreases in both the cases.
The amplitude of oscillation in the first case changes by a factor of √(M/(m+M)), whereas in the second case it remains unchanged
The final time period of oscillation in both cases is the same
The total energy decreases in both cases
In case I,
From Conservation of momentum, MV1 = (M+m)V2
MV1/(M+m) = V2
√(k(M+m)A2²) = M/(M+m) √(kMA1²)
A2 = √(M/(M+m))A1
In case II,
A2 = A1
T = 2π√((M+m)/k) in both cases.
Total energy decreases in the first case whereas it remains the same in the second case. Instantaneous speed at x0 decreases in both cases.
Answer is A, B, and D.