Eduprobe
Question:
A body of mass m and charge q is connected to a spring of spring constant k. It is oscillating along the x-direction about its equilibrium position, taken to be at x=0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?
The new equilibrium position is at a distance: qE/2k from x=0
The total energy of the system is 1/2mω²A² + 1/2q²E²/k
The total energy of the system is 1/2mω²A² - 1/2q²E²/k
The new equilibrium position is at a distance: 2qE/k from x=0
Solution:
When electric field is applied, at equilibrium F=kx=qE, x = qE/k, x - extension of spring
Total Energy of system = Kinetic energy + Potential energy
T.E. = 1/2mv² + 1/2kx² = 1/2mω²A² + 1/2q²E²/k