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Question:

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be:

10√2 m

20 m

20√2 m

10 m

Solution:

As we know that, hmax = u² / 2g = 10
where hmax is the maximum height, u is the initial velocity, and g is the acceleration due to gravity.
The maximum horizontal distance (R) is given by the formula:
R = u² / g
Since hmax = u² / 2g = 10, we can write u² = 20g.
Substituting this into the formula for R, we get:
R = (20g) / g = 20 m
Therefore, the maximum horizontal distance that the boy can throw the stone is 20 m.