10√2 m
20 m
20√2 m
10 m
As we know that, hmax = u² / 2g = 10
where hmax is the maximum height, u is the initial velocity, and g is the acceleration due to gravity.
The maximum horizontal distance (R) is given by the formula:
R = u² / g
Since hmax = u² / 2g = 10, we can write u² = 20g.
Substituting this into the formula for R, we get:
R = (20g) / g = 20 m
Therefore, the maximum horizontal distance that the boy can throw the stone is 20 m.