A bucket opens at the top, and made up of a metal sheet is in the form of a frustum of a cone. The depth of the bucket is 24 cm and the diameters of its upper and lower circular ends are 30 cm and 10 cm respectively. Find the cost of metal sheet used in it at the rate of Rs 10 per 100 cm². [Use π=3.14]. Insert answer in nearest integer.

Diameter of upper end of bucket = 30 cm
Diameter of lower end of bucket = 10 cm
Then, radius of upper end of bucket r1 = 30/2 = 15 cm
And, radius of lower end of bucket r2 = 10/2 = 5 cm
Height of bucket = 24 cm
Slant height of bucket = √(r2 - r1)² + h² = √(15 - 5)² + (24)² = √(10)² + (24)² = √100 + 576 = √676 = 26 cm
Area of metal sheet used to make bucket = π(r1 + r2)l + π(r2)² = π(15 + 5)26 + π(5)² = 520π + 25π = 545π cm²
Given cost of 100 sq cm metal sheet = Rs. 10
Cost of 545π cm² metal sheet = 545 × 3.14 × 10 / 100 = 171.13 Rs.
Cost of metal sheet used for making bucket = Rs. 171.13