A bullet of mass 20g has an initial speed of 1ms⁻¹, just before it starts penetrating a mud wall of thickness 20cm. If the wall offers a mean resistance of 2.5×10⁻²N, the speed of the bullet after emerging from the other side of the wall is close to:
0.1ms⁻¹
0.7ms⁻¹
0.3ms⁻¹
0.4ms⁻¹
Solution:
The correct option is D 0.7ms⁻¹ m=20g,u=1m/s,v=? S=20×10⁻²m a=-2.5×10⁻²/20×10⁻³m/s² v²=u²+2as v²=1-2×2.5×10⁻²/20×10⁻³×20×10⁻² v=1-√2≈0.7m/s