(1−d/R)
(R−d/R+d)
(1+d/R)
(R+d/R−d)
When the capillary is placed in water on the surface of earth, the acceleration due to gravity is g. Since, the rise in the capillary tube is directly proportional to the acceleration due to gravity, Hence, when the entire apparatus is taken into a mine of depth d, the value of acceleration due to gravity will become, g'(1-d/R). Thus, the rise in the capillary tube will be x, y in the 2 cases. So, x/y = g/g'(1-d/R) = 1/(1-d/R)