A Carnot engine has an efficiency of 1/6. When the temperature of the sink is reduced by 62oC, its efficiency is doubled. The temperatures of the source and the sink are, respectively?

Given,
1/6 = 1 - T_sink/T_source → T_sink/T_source = 5/6.. (1)
Also, 2/6 = 1 - (T_sink - 62)/T_source → 62/T_source = 4/6.. (2)
∴T_source = 372K = 99oC
Also, T_sink = (5/6) × 372 = 310K = 37oC
(Note :- Temperature of source is more than temperature of sink)