Eduprobe
Question:
A Carnot's engine works as a refrigerator between 250K and 300K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:
420J
772J
2520J
2100J
Solution:
COP = T1/(T2-T1) = 250/300-250 = 5
COP = 5 = QL/W
W = 500 × 4.184/5 = 420J