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Question:

A carrier wave of peak voltage 15 V is used to transmit a message signal. Find the peak voltage of the modulating signal in order to have a modulation index of 60%.

Solution:

Given:
Carrier wave peak voltage (Ac) = 15 V
Modulation index (μ) = 60% = 0.6

The modulation index (μ) is defined as the ratio of the peak voltage of the modulating signal (Am) to the peak voltage of the carrier wave (Ac):

μ = Am / Ac

We need to find the peak voltage of the modulating signal (Am). We can rearrange the formula to solve for Am:

Am = μ * Ac

Substituting the given values:

Am = 0.6 * 15 V

Am = 9 V

Therefore, the peak voltage of the modulating signal is 9 V.