Q4πϵ₀(a²+b²+c²)(a³+b³+c³)
Q(a+b+c)4πϵ₀(a²+b²+c²)
Q4πϵ₀(a+b+c)
Q12πϵ₀(ab+bc+ca)abc
Potential at point P, V = kQ/a + kQ/b + kQ/c ≈ Q/a : Q/b : Q/c since σa = σb = σc ∴ Qa = [a²/a²+b²+c²]Q Qb = [b²/a²+b²+c²]Q Qc = [c²/a²+b²+c²]Q V = Q4πε₀[(a+b+c)/a²+b²+c²] ∴ correct answer is (2).