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Question:

A chord of a circle of radius 10cm subtends a right angle at its centre. The length of the chord (in cm) is

5√2

5√2

10√2

10√3

Solution:

Given in ΔAOC, OA=10cm, OB=10cm and ∠AOB=90⁰
Using Pythagoras theorem in ΔAOB
we can get AB
AB = √OA² + OB² = √10² + 10² = 10√2 cm.
Hence, length of the chord AB is 10√2 cm.