2x-y+10=0
5x+2y+4=0
3x+4y-9=0
4x+5y-6=0
(-2,4) and touches the y-axis at (0,2)
Radius of circle = 2 units
From the figure we can see that (-2,4) is the end point of diameter whose other end is (-2,0).
So, centre of this circle is (-2,2).
By substituting the point (-2,2) in the equations given in the options, we can see that, only 2x-y+10=0 passes through (-2,2).