9.54µH
7.54µH
8.54µH
10.54µH
Given : Number of turns in coil N₂ = 10
Number of turns per unit length in solenoid, n = 15 per cm = 1500 turns per meter
Area of the coil A₂ = 4 cm² = 4 × 10⁻⁴ m²
Mutual inductance M = μ₀nN₂A₂cosθ, where θ is the angle between →B and →A₂
∴M = 4π × 10⁻⁷ × 1500 × 10 × 4 × 10⁻⁴ × 1 (∵ θ = 0°)
⇒M = 7.54 × 10⁻⁶ H = 7.54 µH