A circular wire loop of radius R is placed in the x-y plane centered at the origin O. A square loop of side a (a<<R) having two turns is placed with its center at z=√3R along the axis of the circular wire loop. The plane of the square loop makes an angle of 45° with respect to the z-axis. If the mutual inductance between the loops is given by μ₀a²2p/2R, then the value of p is?
14
7
17
8
Solution:
M=NΦI=2μ₀IR²/(2(8R³))a²cos45°I=μ₀a²/(8R) × 2(1/√2) = μ₀a²/R × √2/8 So, p=7