A condenser of 250µF is connected in parallel to a coil of inductance 0.16 mH, while its effective resistance is 20Ω. Determine the resonant frequency.
8×10⁵Hz
9×10⁴Hz
9×10³Hz
16×10⁷Hz
Solution:
For the given case we have standard formula for resonant frequency as: f=1/(2π√(LC−R²/4L²)) f=1/(2π√(0.16×10⁻³×250×10⁻⁶−(0.16×10⁻³)²)) On directly putting the given values in he equation we get: ω=7.98×10⁵