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Question:

A condenser of 250µF is connected in parallel to a cell of inductance 0.16 mH. Determine the resonant frequency.

9×10⁴Hz

9×10³Hz

8×10⁵Hz

16×10⁷Hz

Solution:

Correct option is C. 8×10⁵Hz
Given
Capacitance, C = 250µF = 250 × 10⁻⁶ F
Inductance, L = 0.16mH = 0.16 × 10⁻³ H
Resonant frequency, f = 1/(2π√LC) = 1/(2 × 3.14 × √(250 × 10⁻⁶ × 0.16 × 10⁻³)) = 8 × 10⁵Hz