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Question:

A conducting sphere of radius R carrying charge Q lies inside an uncharged conducting shell of radius 2R. If they are joined by a metal wire, the amount of heat that will be produced is:

14πε₀.Q²/R

14πε₀.Q²/2R

14πε₀.Q²/4R

24πε₀.Q²/3R

Solution:

When connected by metal wire, whole of the charge would be transferred to the outer conducting shell. Capacitance of the two system are Ci = 4πε₀(R) and Cf = 4πε₀(2R) Thus initial energy = Q²/2Ci Final energy = Q²/2Cf The energy amount of heat produced is equal to the change in potential energy of the system = Q²/2Ci − Q²/2Cf = 14πε₀.Q²/4R