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Question:

A cone of base radiusRand heighthis located in a uniform electric field→Eparallel to its base. The electric flux entering the cone is:4EhR2EhR12EhREhRA cone of base radiusRand heighthis located in a uniform electric field→Eparallel to its base. The electric flux entering the cone is:4EhR2EhR12EhREhRRRRRRhhhhh→E→E→E→E→E→→→EEE4EhR4EhR4EhR4EhR44EEhhRR2EhR2EhR2EhR2EhR22EEhhRR12EhR121212121212121212111222EhREhREhREEhhRREhREhREhREhREEhhRRA4EhR4EhR4EhR4EhR4EhR44EEhhRRB2EhR2EhR2EhR2EhR2EhR22EEhhRRCEhREhREhREhREhREEhhRRD12EhR12EhR121212121212121212111222EhREhREhREEhhRR?

4EhR

2EhR

EhR

12EhR

Solution:

We know that,ϕ=E.ACosθFlux crossing through the area of cone parallel to the electric field which is nothing but a right angle triangle having base2Rand heighththerefore,ϕ=EhR