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Question:

A conical pendulum of length 1 m makes an angle θ=45° w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be : (Take g=10ms⁻²) 0.4 m/s, 4m/s, 2 m/s, 0.2 m/s

0.4 m/s

4m/s

0.2 m/s

2 m/s

Solution:

The correct option is A
0.4 m/s
l=1m
r=0.4m
θ=45°
F=mv²/r
[T²]=mg
[T²]=F
F=mg
mv²/r=mg
v²=rg
=0.4 × 10
=4
v=2m/s