A conical pendulum of length 1 m makes an angle θ=45° w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be : (Take g=10ms⁻²) 0.4 m/s, 4m/s, 2 m/s, 0.2 m/s
0.4 m/s
4m/s
0.2 m/s
2 m/s
Solution:
The correct option is A 0.4 m/s l=1m r=0.4m θ=45° F=mv²/r [T²]=mg [T²]=F F=mg mv²/r=mg v²=rg =0.4 × 10 =4 v=2m/s