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Question:

A current of 2mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11V is connected across it is :

11×10𕒹W

11×105W

11×10𕒸W

11×10𕒷W

Solution:

The correct option is A
11×10𕒹W
P=I²R
4.4= (2×10⁻³)²R
R=1.1×10⁶ Ω
P₁=V²/R = 11²/1.1×10⁶ = 11×10⁵ W