√87
√1514
1514
87
a=gsinθ1+k^2/r^2
Substituting k for cylinder as √(1/2)r and for sphere as √(2/5)r we get
The acceleration of a cylinder rolling down an incline is ac=2/3gsinθc
Similarly, for sphere, as=5/7gsinθs
Since, the two accelerations are equal,
sinθc/sinθs=15/14