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Question:

A cylindrical tube, open at both ends, has a fundamental frequency, v, in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column now is?

v2

v

3v4

2v

Solution:

f=v/2l
Now, it will act as one end open and one end closed.
So,f0=v/2l'=v/4l/2=v/2l=f