devarshi-dt-logo

Question:

A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is Ti (in Kelvin) and the final temperature is aTi, the value of a is?

5

4

2

3

Solution:

For adiabatic process, we can write TVγ = constant
γ = 7/5 for diatomic gases
TiV7/5 = k (constant) ---- initial condition
aTiV7/5 = k (constant) ---- final condition
TV7/5 = aT(V/32)7/5
∴ a = 4