A diode detector is used to detect an amplitude modulated wave of 60?

We know that the frequency will be given by: f = 1/(2πμτ) For a combination of resistance and capacitance, τ = RC Therefore, frequency can be given as: f = 1/(2πμRC) So, μ = 0.6 , R = 100KΩ , C = 250 × 10⁻¹²F f = 1/(2π × 0.6 × 100 × 10³ × 250 × 10⁻¹²) f = 1/(942.477 × 10⁻⁶) f ≈ 1061 Hz ≈ 10.61 KHz