(A) : Initial speed of the car A u=52km/h = 52 × 5/18 = 14.44 m/s
The car stops in 5 seconds i.e v=0 at t=5
(A) : Initial speed of the car A u=3km/h = 3 × 5/18 = 0.83 m/s
The car stops in 10 seconds i.e v=0 at t=10
With the help of these initial and final points for both the cases, we can plot the graph of speed vs time.
Area under the speed-time graph gives the distance covered.
∴Distance covered by car A = 1/2 × 14.44 × 5 = 36.1 m
∴Distance covered by car B = 1/2 × 0.83 × 10 = 4.15 m
Thus car A travels more distance than B.