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Question:

A force F acting on an object varies with distance x as shown in the figure. The force is in N and x in m. The work done by the force in moving the object from x=0 to x=6 m is:

15 J

13.5 J

20 J

10 J

Solution:

Work done in moving the object by distance x = ∫₀ˣF.dx = Area under the given curve [from x=0m to x=6m] = (3×3) + (1/2×3×3) = 13.5J