2.5×10⁻⁶Ω
1.25×10⁻⁷Ω
1.25×10⁻⁶Ω
2.5×10⁻⁷Ω
formula : S= GIg/ (I-Ig)
where S= shunt resistance , (I-Ig)= current through the shunt resistance , I=Current in the circuit.
Here, galvanometer resistance ,G= 25 ohm ; Ig= 0.001 A , I= 2A
S= (25 0.001 )/( 2- 0.001)=1.25×10⁻⁷Ω
A shunt resistance of 1.25×10⁻⁷Ω must be connected to make the galvanometer in the range of 0 to 2A