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Question:

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig.15.5), and these are equally likely outcomes. What is the probability that it will point at (i) 8?

Solution:

i) P(8) = 1/8
ii) P(Odd number) = Number of odd numbers / Total number of numbers in the chart
P(Odd number) = 4/8 = 1/2
iii) P(Number > 2) = Number of numbers > 2 / Total number of numbers in the chart
P(Number > 2) = 6/8 = 3/4
iv) P(Number < 9) = Number of numbers < 9 / Total number of numbers in the chart
P(Number < 9) = 8/8 = 1