0.16(AA);0.24(Aa);0.36(aa
0.36(AA);0.48(Aa);0.16(aa
0.16(AA);0.48(Aa);0.36(aa
0.16(AA);0.36(Aa);0.48(aa
Correct option is C. 0.16(AA); 0.48(Aa); 0.36(aa)
Frequency of dominant allele (say p) = 0.4
Frequency of recessive allele (say q) = 1 – 0.4 = 0.6
∴Frequency of homozygous dominant individuals (AA) = p² = (0.4)² = 0.16
Frequency of heterozygous individuals (Aa) = 2pq = 2(0.4)(0.6) = 0.48
Frequency of homozygous recessive individuals (aa) = q² = (0.6)² = 0.36.
So, the correct answer is '0.16(AA); 0.48(Aa); 0.36(aa)'.