A heating element has a resistance of 100Ω at room temperature. When it is connected to a supply of 220 V, a steady current of 2A passes in it and temperature is 500℃ more than room temperature. What is the temperature coefficient of resistance of the heating element?

We know that resistance R = V/i = 220/2 = 110Ω
Also R = R₀(1 + αΔT)
where R₀ is the initial resistance at room temperature, α is the temperature coefficient of resistance, and ΔT is the change in temperature.
R₀ is given as 100Ω.
Putting ΔT = 500K (assuming Celsius is used), we get
110 = 100(1 + α × 500)
1.1 = 1 + 500α
0.1 = 500α
α = 0.1/500 = 0.0002 = 2 × 10⁻⁴ ℃⁻¹
Note: The provided solution in the input data appears to have an error. The calculation above shows a more accurate result. The options provided seem to be using a different unit (possibly a different power of 10). The calculated value is 2 × 10⁻⁴ ℃⁻¹, which is not among the options. There may be an issue with the question or the options provided.