g30
g5
g20
g10
The correct option is A
60 = √(Mg/μ)
60.5 = √(M(g² + a²)¹/²/μ)
=> 60.5/60 = √(g² + a²)/g
=> (1 + 0.5/60)² = (g² + a²)/g²
=> (1 + 1/120)² = 1 + a²/g²
=> 1 + 2/120 = 1 + a²/g² (approx)
=> a²/g² = 1/60
=> a² = g²/60
=> a = g/√60 ≈ g/8 ≈ g/10 ≈ g5