A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope. Find (i) the area of that part of the field in which the horse can graze. (ii) The increase in the grazing area if the rope were 10 m long instead of 5 m. (Use π=3.14)

Side of square field=15 m
Length of rope=5 m=radius of the quadrant
The area available for the horse to graze = Area of Quadrant of a circle
∴Area of Quadrant having radius 5 cm= π × r² / 4 = 3.14 × 5 × 5 / 4 = 78.5 / 4 = 19.625 m²
If the length of rope is increased to 10m, then the new radius= 5 + 5 = 10 m
∴Area of new quadrant having radius 10 cm= π × r² / 4 = 3.14 × 10 × 10 / 4 = 314 / 4 = 78.5 m²
∴Increase in grazing area= Area of new quadrant having radius 10 cm - Area of Quadrant having radius 5 cm = 78.5 - 19.625 = 58.875 m²