[π/4, π/2]
[0, π/4]
[π/6, π/3]
[π/3, π/2]
Sum of square of direction cosines is 1. Let's assume α is the angle with x, β with y and γ with z. α, β, γ ∈ [0, π/2]
Now, cos²α + cos²β + cos²γ = 1
But it is given that, α = β = θ
∴ cos²θ + cos²θ + cos²γ = 1
⇒ 2cos²θ = 1 - cos²γ
⇒ 2cos²θ = sin²γ
⇒ cosθ = sinγ / √2
As γ ∈ [0, π/2], then θ ∈ [π/4, π/2]