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Question:

A magnetic moment of 1.73 BM will be shown by which one among the following?

[Cu(NH3)4]2+

TiCl4

[CoCl6]4−

[Ni(CN)4]2−

Solution:

A magnetic moment of 1.73 BM will be shown by [Cu(NH3)4]2+. Magnetic moment is given by the expression (μ) = √n(n+2). 1.73 = √n(n+2). n = 1. So, the compound must contain one unpaired electron. The compound is [Cu(NH3)4]2+ as Cu2+ has a 3d9 electronic configuration.