A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R. Assuming the pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is :
3/2g
g
g/3
2/3g
Solution:
Equations of motion are: mg - T = ma (i) T ⋅ R = 1/2mR2 α (ii) and a = Rα (iii) From (ii) and (iii), we get: T = 1/2 m a Substituting this value of T in (i), we get: mg - 1/2 ma = ma mg = 3/2 ma a = 2/3 g