A mass 'm' is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?
g/2
5g/6
2g/3
g
Solution:
a = Rα (no slipping) Also, τ = Iα and τ = TR Using the relations, ⇒ T = Ia/R² For hollow cylinder, I = mR² ⇒ T = ma Now for block, ma = mg - T ma = mg - ma ⇒ a = g/2